Question

How do you evaluate the definite integral `int (2x^-2-3) dx` from `[1,2]`?

Answer 1

`-2`

Explanation:

`int_1^2 (2x^-2-3)dx = int_1^2 (2x^-2)dx - int_1^2 3dx`

Applying the power rule to each integral:

`= (2x^-1)/-1]_1^2 - 3x]_1^2`

`= (-2)/x]_1^2 - 3x]_1^2`

`=-1-(-2)-(6-3)`

`=1-3 =-2`