How do you evaluate the definite integral #int 2x+3# from #[1,3]#?
1 Answer
Aug 16, 2016
Explanation:
To evaluate
#int_1^3(2x+3)dx# integrate using the
#color(blue)"power rule"#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))#
#rArrint_1^3(2x+3)dx=[x^2+3x]_1^3# now evaluate function at upper limit and subtract the evaluation at the lower limit.
#rArr[x^2+3x]_1^3=(9+9)-(1+3)=18-4=14#
