How do you evaluate the definite integral #int dx/x# from #[1,e]#?
1 Answer
#int_1^e \ 1/x \ dx = 1#
Explanation:
The following are important calculus results
#d/dx(e^x) = e^x => d/dx(lnx)=1/x => int \ 1/x \ dx = lnx#
And so
#int_1^e \ 1/x \ dx = [lnx]_1^e =lne-ln1=1-0=1#
