How do you evaluate the definite integral #int sintheta # from [0, 3pi/4]?
1 Answer
Feb 8, 2017
Explanation:
Using the standard integral.
#color(orange)"Reminder"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(intsinthetad theta=-costheta)color(white)(2/2)|)))#
#rArrint_0^((3pi)/4)sinthetad theta#
#=[-costheta]_0^((3pi)/4)#
#=(-cos((3pi)/4)-(-cos0))#
#=-1/sqrt2+1=1/sqrt2(sqrt2-1)#
