How do you evaluate the definite integral #int (x+1)dx# from [1,5]?
1 Answer
Oct 26, 2017
Explanation:
#"integrate each term using the "color(blue)"power rule"#
#•color(white)(x)int(ax^n)=a/(n+1)x^(n+1)to(n!=-1)#
#rArrint_1^5(x+1)dx#
#=[1/2x^2+x]_1^5#
#=(25/2+5)-(1/2+1)#
#=16#
