Question

How do you evaluate the definite integral `int x^3 dx` from `[0,4]`?

Answer 1

The answer is `=64`

Explanation:

We need

`intx^ndx=x^(n+1)/(n+1)+C(n!=-1)`

Therefore,

`int_0^4x^3dx=[x^4/4]_0^4`

`=(4^4/4-0)`

`=4^3=64`