How do you evaluate the definite integral $int (x+4)dx$ from [-1,3]?

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Answer 1 · 2018-07-04T22:24:00

$39/4$

$\int_-1^3(x+4)\ dx$

$=(x^2/2+4x)_-1^3$

$=3^2/2+4(3)-1^2/2-4(1)$

$=39/4$

How do you evaluate the definite integral int (x+4)dxint (x+4)dx from [-1,3]?