How do you evaluate the definite integral #int x+7x^2 dx# from #[3,4]#?

Question

2324 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-09T16:20:29

#int _3^4 (x+7x^2)d x=89.8bar 3#

#int _3^4 (x+7x^2)d x=?#

#int _3^4 (x+7x^2)d x=|1/2 x^2+7/3 x^3|_3^4#

#int _3^4 (x+7x^2)d x=[1/2*4^2+7/3*4^3]-[1/2*3^2+7/3*3^3]#

#int _3^4 (x+7x^2)d x=[16/2+448/3]-[9/2+189/3]#

#int _3^4 (x+7x^2)d x=16/2-9/2+448/3-189/3#

#int _3^4 (x+7x^2)d x=7/2+259/3#

#int _3^4 (x+7x^2)d x=(21+518)/6#

#int _3^4 (x+7x^2)d x=539/6#

#int _3^4 (x+7x^2)d x=89.8bar 3#