How do you evaluate the expression #3x^2+y# if #x=1# and #y=-3#?
1 Answer
Jan 27, 2016
0
Explanation:
To evaluate substitute the values of x = 1 and y = - 3 into
the expression.
#3x^2 = 3 xx x xx x = 3 xx 1 xx 1 = 3 # so
# 3x^2 + y = 3 - 3 = 0#
