How do you evaluate the expression #(4-y)/(1-x)# when x=2 and y=3?

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Answer 1 · 2018-03-12T20:51:54

Refer to the explanation.

Given:

#(4-y)/(1-x),#

where #x=2# and #y=3#.

Substitute #2# for #x# and #3# for #y#.

#(4-3)/(1-2)#

Simplify.

#1/(-1)=#

#-1#

Answer 2 · 2018-03-12T20:54:20

#-1#

Simply substitute the values of #x(2)# and #y(3)# given into the expression.

#(4-3)/(1-2)=-1/1=-1#