How do you evaluate the expression below when #-2x-8-(-3x+8)# when #x=3#?
1 Answer
Feb 2, 2016
- 13
Explanation:
the first thing to do is distribute the bracket and collect like
terms.so - 2x - 8 + 3x - 8 = x - 16
x=3 : then x - 16 = 3 - 16 - -13
Here is a check doing it the 'long way'
x= 3 : -2(3) - 8 - (- 3(3) + 8 ) = -6 -8 -( - 9 + 8 )
= - 6 - 8 - (-9 + 8 ) = -6 - 8 - (-1) = -6 - 8 + 1 = - 13