How do you evaluate the expression #(y-(-5))/(x-3)# when x=2 and y=5?

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Answer 1 · 2017-01-18T14:53:18

The answer is #-10#. Explanation below.

First, substitute the values #2# for #x# and #5# for #y#:

#(5 - (-5))/(2-3)#

Recall that #a - (-b) = a + b#

#(5 + 5)/(2-3) = 10/(-1) = -10#.

Answer 2 · 2017-01-18T14:54:16

See the entire evaluation process below:

To evaluate this expression substitute #color(red)(2)# for #color(red)(x)# and #color(blue)(5)# for #color(blue)(y)#:

#(color(blue)(y) - (-5))/(color(red)(x) - 3)# giving:

#(color(blue)(5) - (-5))/(color(red)(2) - 3)#

Next, rewrite the numerator of this expression to eliminate the double negative sign. Remember, #color(blue)(- - = +)#

#(color(blue)(5) + 5)/(color(red)(2) - 3)#

Now we can complete the evaluation:

#10/-1 -> -10#