How do you evaluate the following expression when x = 3 and y = 4: for #(y - x)^2#?

1 Answer
Aldrich
Sep 9, 2015

#(y-x)^2# at #x=3# and #y=4# is #1#.

Explanation:

To evaluate an expression means to get its value when you plug in values for variables.

You're given the values #x=3# and #y=4#.
To evaluate #(y-x)^2# for those values, you should plug in the values, meaning you should replace all #x#s with the value #3# and all #y#s with the value #4#.

#(y-x)^2#
#=> (4-3)^2#

Now we can simplify the expression.

#(4-3)^2#
#=1^2#
#=1#

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