# How do you evaluate the function #f(x)=2.3^x# at the value of #x=3/2#?

##### 1 Answer

Jan 13, 2018

#### Explanation:

#"to evaluate substitute "x=3/2" into "f(x)#

#rArrf(color(red)(3/2))=2xx3^(color(red)(3/2))#

#color(white)(xxxxxxx)=2xxsqrt(3^3)#

#color(white)(xxxxxxx)=2sqrt27~~10.39" to 2 dec. places"#