How do you evaluate the function #f(x)=2.3^x# at the value of #x=3/2#?
1 Answer
Jan 13, 2018
Explanation:
#"to evaluate substitute "x=3/2" into "f(x)#
#rArrf(color(red)(3/2))=2xx3^(color(red)(3/2))#
#color(white)(xxxxxxx)=2xxsqrt(3^3)#
#color(white)(xxxxxxx)=2sqrt27~~10.39" to 2 dec. places"#
