How do you evaluate the function #f(x)=2x^2-2x+9# for f(3/2)?
1 Answer
Jun 4, 2018
Explanation:
#"to evaluate "f(3/2)" substitute "x=3/2" into "f(x)#
#f(color(red)(3/2))=2xx(color(red)(3/2))^2-2xxcolor(red)(3/2)+9#
#color(white)(xxxxx)=2xx9/4-3+9#
#color(white)(xxxxx)=9/2+6=9/2+12/2=21/2#
