Question

How do you evaluate the function `f(x) = 3/4x^2 - 11` for `f(2)`?

Answer 1

See a solution process below:

Explanation:

For each occurrence of `color(red)(x)` in `f(x)` substitute `color(red)(2)` and then evaluate the function:

`f(color(red)(x)) = 3/4color(red)(x)^2 - 11` becomes:

`f(color(red)(2)) = (3/4 xx color(red)(2)^2) - 11`

`f(color(red)(2)) = (3/4 xx 4) - 11`

`f(color(red)(2)) = 3 - 11`

`f(color(red)(2)) = -8`