How do you evaluate the function #f(x) = 3/4x^2 - 11# for #f(2)#?

1 Answer
Mar 20, 2018

See a solution process below:

Explanation:

For each occurrence of #color(red)(x)# in #f(x)# substitute #color(red)(2)# and then evaluate the function:

#f(color(red)(x)) = 3/4color(red)(x)^2 - 11# becomes:

#f(color(red)(2)) = (3/4 xx color(red)(2)^2) - 11#

#f(color(red)(2)) = (3/4 xx 4) - 11#

#f(color(red)(2)) = 3 - 11#

#f(color(red)(2)) = -8#