How do you evaluate the function #f (x) = 3x^2 + 3x -2# for #2f (a)#?
1 Answer
May 2, 2018
Explanation:
#"evaluate "f(a)" by substituting x = a into "f(x)#
#rArrf(color(red)(a))=3(color(red)(a))^2+3(color(red)(a))-2#
#color(white)(xxxxxx)=3a^2+3a-2#
#rArr2f(a)=2(3a^2+3a-2)=6a^2+6a-4#
