Question

How do you evaluate the function `f (x) = 3x^2 + 3x -2` for `f (a) + f (2)`?

Answer 1

`f(a) + f(2) = 3a^2 + 3a + 14`

Explanation:

When evaluating a function `f(x)` at some specific value, you simply replace `x` with that value wherever `x` appears in the function.
So

`f(a) = 3a^2 + 3a - 2`

and

`f(2) = 3(2)^2 + 3(2) - 2 = 12+6-2 = 16`

Thus

`f(a) + f(2) = (3a^2 +3a - 2) + 16 = 3a^2 + 3a + 14`