Question

How do you evaluate the function `f(x)= -x^2 + 5` for `f (4)`?

Answer 1

See a solution process below:

Explanation:

For each occurrence of `color(red)(x)` in `f(x)` substitute `color(red)(4)` and calculate the result:

`f(color(red)(x)) = -color(red)(x)^2 + 5` becomes:

`f(color(red)(4)) = -color(red)(4)^2 + 5`

`f(color(red)(4)) = -16 + 5`

`f(color(red)(4)) = -11`