How do you evaluate the function g(x)=3-2/3x for g(3)?

May 6, 2018

$g \left(3\right) = 3 - \frac{2}{3} \cdot \left(3\right) = 3 - 2 = 1$

Explanation:

show that

$g \left(x\right) = 3 - \frac{2}{3} x$

for $g \left(3\right)$

$g \left(3\right) = 3 - \frac{2}{3} \cdot \left(3\right) = 3 - 2 = 1$

May 6, 2018

$g \left(3\right) = 1$

Explanation:

Plug $3$ in for $x$:

$g \left(3\right) = 3 - \frac{2}{3} \cdot 3$

$\frac{2}{3} \cdot \frac{3}{1} = \frac{2}{\cancel{3}} \cdot \frac{\cancel{3}}{1} = 2$

$g \left(3\right) = 3 - 2$

$g \left(3\right) = 1$