How do you evaluate the function #g(x)=3-2/3x# for #g(3)#?

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Answer 1 · 2018-05-06T22:56:57

The answer
#g(3)=3-2/3*(3)=3-2=1#

show that

#g(x)=3-2/3x#

for #g(3)#

#g(3)=3-2/3*(3)=3-2=1#

Answer 2 · 2018-05-06T23:25:26

#g(3)=1#

Plug #3# in for #x#:

#g(3)=3-2/3*3#

#2/3*3/1=2/cancel(3)*cancel(3)/1=2#

#g(3)=3-2#

#g(3)=1#