Question

How do you evaluate the function `g(x)=3-2/3x` for `g(-3)`?

Answer 1

5

Explanation:

`g(`thing`)` `= 3 - 2/3 times`thing

thing = -3

`g(-3) = 3 - 2/3 times (-3)`

`= 3 -2 times (-1)`

`= 3 + 2`