# How do you evaluate the function h(x)= .2x^2 - .6x - .25 for h(-1/2)?

Nov 22, 2015

$h \left(- \frac{1}{2}\right) = 0.1$

#### Explanation:

Substituting $\left(- \frac{1}{2}\right)$ for $x$ in $h \left(x\right) = 0.2 {x}^{2} - 0.6 x - 0.25$
gives
$\textcolor{w h i t e}{\text{XXX}} h \left(- \frac{1}{2}\right) = 0.2 \times {\left(- \frac{1}{2}\right)}^{2} - 0.6 \times \left(- \frac{1}{2}\right) - 0.25$

$\textcolor{w h i t e}{\text{XXXXXXXX}} = \left(0.2 \times \frac{1}{4}\right) - \left(- 0.3\right) - 0.25$

$\textcolor{w h i t e}{\text{XXXXXXXX}} = 0.05 + 0.3 - 0.25$

$\textcolor{w h i t e}{\text{XXXXXXXX}} = 0.1$