# How do you evaluate the function h(x)=-x^2+10 when x=3?

$h \left(3\right) = 1$
If $h \left(\textcolor{b l u e}{x}\right) = - {\textcolor{b l u e}{x}}^{2} + 10$
${\textcolor{w h i t e}{\text{XX")h(color(blue)3)=-color(blue)(} \left(3\right)}}^{2} + 10$
$\textcolor{w h i t e}{\text{XXXxx}} = - 9 + 10$
$\textcolor{w h i t e}{\text{XXXxx}} = 1$