How do you evaluate the function #p(x)=x^2-2# for #p(-2)#?

Question

2219 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-14T12:48:42

#p(-2)=2#

#p(x)=x^2-2#

When #x=-2#, #p(x)=p(-2)#

#p(-2)=(-2)^2-2#
#color(white)(p(-2))=2#

Answer 2 · 2018-05-14T12:51:10

I tried this:

When you write:

#p(-2)#

it means that you want to evaluate your function for #x=-2#, so you need to subtitute #x# for #-2# in #p#:

#p(-2)=(-2)^2-2#

as you can see #x# became #-2#. Let us evaluate the value of our function at this value of #x#:

#p(-2)=color(red)(4)-2=2#

because: #(-2)^2=4#