# How do you evaluate the function when x = -3, 0, and 2 for h(x) = 3.25x?

Jul 14, 2018

h(-3) = -9.75; " "h(0) = 0; " "h(2) = 6.5

#### Explanation:

Given: Evaluate $h \left(x\right) = 3.25$ at $x = - 3 , 0 , 2$

$h \left(- 3\right) = 3.25 \left(- 3\right) = - 9.75$

$h \left(0\right) = 3.25 \left(0\right) = 0$

$h \left(2\right) = 3.25 \left(2\right) = 6.5$