# How do you evaluate the function with the given values of x: f(x)=(1/3)[2x] x=-1, x=1/2?

$- \frac{2}{3} \text{ and } \frac{1}{3}$
$\text{substitute the given values of x into } f \left(x\right)$
$f \left(\textcolor{red}{- 1}\right) = \frac{1}{3} \times \left(2 \times \textcolor{red}{- 1}\right) = \frac{1}{3} \times - 2 = - \frac{2}{3}$
$f \left(\textcolor{red}{\frac{1}{2}}\right) = \frac{1}{3} \times \left(2 \times \textcolor{red}{\frac{1}{2}}\right) = \frac{1}{3} \times 1 = \frac{1}{3}$