# How do you evaluate the function with the given values of x: h(x)=4x^-2 x=2, x=3?

$\therefore h \left(2\right) = 1 \mathmr{and} h \left(3\right) = \frac{4}{9}$
h(x) = 4 x^(-2)=4/x^2 ; x=2 , x=3
$\therefore h \left(2\right) = 4 \cdot {2}^{- 2} = \frac{4}{2} ^ 2 = 1$
$\therefore h \left(3\right) = 4 \cdot {3}^{- 2} = \frac{4}{3} ^ 2 = \frac{4}{9}$ [Ans]