Question

How do you evaluate the function with the given values of x: h(x)=4x^-2 x=2, x=3?

Answer 1

`:. h(2) =1 and h(3) =4/9`

Explanation:

`h(x) = 4 x^(-2)=4/x^2 ; x=2 , x=3`

`:. h(2) = 4 * 2^(-2)= 4/2^2=1`

`:. h(3) = 4 * 3^(-2)= 4/3^2=4/9` [Ans]