How do you evaluate the indefinite integral #int (x^3+3x+1)dx#?
1 Answer
Oct 21, 2017
# int \ x^3+3x+1 \ dx = x^4/4+(3x^2)/2+x + C #
Explanation:
We use the power rule for integration:
# int \ x^n \ dx = x^(n+1)/(n+1) #
So we have:
# int \ x^3+3x+1 \ dx = x^4/4+(3x^2)/2+x + C #
