Question

How do you evaluate the integral `int 1/x^3dx` from -1 to 2?

Answer 1

`3/8`

Explanation:

`int_-1^2 1/x^3 dx = int_-1^2 x^-3 dx`

`= x^-2/-2|_-1 ^2`

`= -1/(2x^2)|_-1 ^2`

`=-1/8- (-1/2)`

`=3/8`