Question

How do you evaluate the integral `int 1/(x(lnx)^2)dx` from `e` to `oo`?

Answer 1

1

Explanation:

`int_e^oo 1/(x(lnx)^2)dx`

`= int_e^oo d/dx (- 1/(lnx) )dx`

`= [ - 1/(lnx) ]_e^oo`

`= [ 1/(lnx) ]_oo^e`

`= 1 - 0 = 1`