How do you evaluate the integral #int 2/x^5 dx# from #-oo# to #-1#?
1 Answer
Aug 1, 2016
Explanation:
We have:
#int_(-oo)^(-1)2/x^5dx=2int_(-oo)^(-1)x^-5dx#
Evaluating the integral:
#=2[x^(-4)/(-4)]_(-oo)^(-1)#
#=-1/2[1/x^4]_(-oo)^(-1)#
#=-1/2[1/(-1)^4-lim_(xrarr-oo)1/x^4]#
#=-1/2[1/1-0]#
#=-1/2#
