# How do you evaluate the integral int dt/(tlnt)?

Jan 14, 2017

The answer is =ln(∣ln(t)∣)+C

#### Explanation:

We do a substitution

Let $u = \ln t$, $\implies$, $\mathrm{du} = \frac{\mathrm{dt}}{\ln} t$

Therefore,

$\int \frac{\mathrm{dt}}{t \ln t} = \int \frac{\mathrm{du}}{u} = \ln u$

=ln(∣ln(t)∣)+C