Question

How do you evaluate the integral `int dt/(tlnt)`?

Answer 1

The answer is `=ln(∣ln(t)∣)+C`

Explanation:

We do a substitution

Let `u=lnt`, `=>`, `du=dt/lnt`

Therefore,

`int(dt)/(tlnt)=int(du)/u=lnu`

`=ln(∣ln(t)∣)+C`