How do you evaluate the integral int e^xdx from -oo to 1? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Alexander Jul 24, 2016 int_(-∞)^(1) e^x dx = e Explanation: Since e^x doesn't really have a discontinuity in the interval, we can simply evaluate the definite integral in a normal procedure. int_(-∞)^(1) e^x dx = [e^x]_(-∞)^(1) = [e - e^(-∞)] = e-0 = e Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of ln(7x)? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of x^2-6x+5 from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral 1/(sqrt(49-x^2)) from 0 to 7sqrt(3/2)? How do you integrate f(x)=intsin(e^t)dt between 4 to x^2? How do you determine the indefinite integrals? How do you integrate x^2sqrt(x^(4)+5)? See all questions in Definite and indefinite integrals Impact of this question 1483 views around the world You can reuse this answer Creative Commons License