Question

How do you evaluate the integral `int e^xdx` from `-oo` to 1?

Answer 1

`int_(-∞)^(1) e^x dx = e`

Explanation:

Since `e^x` doesn't really have a discontinuity in the interval, we can simply evaluate the definite integral in a normal procedure.

`int_(-∞)^(1) e^x dx = [e^x]_(-∞)^(1) = [e - e^(-∞)] = e-0 = e`