How do you evaluate the integral #int x^3e^(-x^2) dx# from 0 to #oo# if it converges?

1 Answer
Oct 12, 2016

You'll need to integrate by parts to evaluate.

Explanation:

#int x^3e^(-x^2) dx = -1/2int underbrace(x^2)_u underbrace(e^(-x^2) (-2)x dx)_(dv)#

# = -1/2 x^2 e^(-x^2)+ int x e^(x^2) dx#

# = -1/2 x^2 e^(-x^2)+ (-1/2) int (-2) x e^(x^2) dx#

# = -1/2x^2 e^(-x^2) - 1/2 e^(-x^2)#

(Of course #+C#, but we're going to use it for a definite integral, so I'll leave that off.)

Evaluate from #0# to #b#, then take the limit as #brarroo# to get

#int_0^oo x^3e^(-x^2) dx = 1/2#