Question

How do you evaluate the limit `(2^x+sinx)/x^4` as x approaches `0`?

Answer 1

`oo`

Explanation:

Let's focus on the numerator first.

`lim_(xrarr0)(2^x + sin(x)) = 2^0 + sin(0) = 1`

Overall limit is:

`lim_(xrarr0)1/(x^4) = oo`