How do you evaluate the limit #-2s^2+8s-8# as s approaches #2#?
1 Answer
Jan 7, 2017
Explanation:
Since this is a polynomial and continuous we can evaluate the limit by substitution.
#rArrlim_(sto2)(-2s^2+8s-8)#
#=-2(2)^2+8(2)-8=-8+16-8=0#
