How do you evaluate the limit #-2w# as #w# approaches #2#?

2 Answers
Nov 2, 2017

#-4#

Explanation:

#lim_(w->2)(-2w)#

Plugging in 2 for w:

#-2(2)=-4#

#:.#

#lim_(w->2)(-2w)=-4#

Nov 2, 2017

-4

Explanation:

...your first step on this type of limit problem is to simply substitute the ending value of the variable into the expression, and see if it makes sense. (i.e., you don't end up dividing by zero).

In this case, just evaluate f(w) = -2w at w = 2. You get -4. So you can get on with your life.

GOOD LUCK.