Question

How do you evaluate the limit `((2y^2+2y+4)/(6y-3))^(1/3)` as y approaches 5?

Answer 1

Since the denominator does not go to `0` and the 3rd root of a real is real, use substitution.

Explanation:

`lim_(yrarr5)((2y^2+2y+4)/(6y-3))^(1/3) = root(3)(64/27) = 4/3`