Question

How do you evaluate the limit `3x^3-2x^2+4` as x approaches `1`?

Answer 1

`lim_(x rarr 1) f(x) = 5`

Explanation:

Let `f(x)=3x^3-2x^2+4`, Then `f(x)` is a polynomial and as such it is continuous `AA x in RR`

So, `lim_(x rarr c) f(x) = f(c) AA x in RR, c in RR`

Hence,
`lim_(x rarr 1) f(x) = f(1) = 3-2+4 = 5`