Question

How do you evaluate the limit `cscx` as x approaches `0^+`?

Answer 1

`+infty`

Explanation:

So we must ask ourselves what is cosecant. This is simple:
`csc(x) = 1/(sin(x))`

Therefore, we know that
`lim_(x to 0^+) csc(x) = (lim_(x to 0^+) sin(x))^(-1)`

Since `sin(x) to 0` as `x to 0` and it approaches it positively, that means that we have `+infty` as the limit as we approach zero from the positive side.