# How do you evaluate the limit lim e^x-x^2 as x->-oo?

Dec 5, 2017

$- \infty$

#### Explanation:

as $x \to - \infty$ , $\textcolor{w h i t e}{88} {e}^{x} \to 0$

as $x \to - \infty$ , $\textcolor{w h i t e}{88} {x}^{2} \to \infty$

$\therefore$

as $x \to - \infty$ , $\textcolor{w h i t e}{88} {e}^{x} - {x}^{2} \to - \infty$

${\lim}_{x \to - \infty} \left({e}^{x} - {x}^{2}\right) = - \infty$