How do you evaluate the limit #lim(x^3+2x^2-4x-8)/(x^2-4)dx# as #x->0#?
1 Answer
Jan 5, 2017
Explanation:
Since the function is not undefined or indeterminate for x = 0 we can evaluate the limit by substitution.
#rArrlim_(xto0)(x^3+2x^2-4x-8)/(x^2-4)#
#=(-8)/(-4)=2#
