# How do you evaluate the limit of #lim (2h^3-h^2+5h)/h# as #h->0#?

##### 2 Answers

May 24, 2017

#### Explanation:

- Both the numerator and denominator are
#0# when#h=0# . We can apply the*L'Hopital's rule*to find the limit. - The limit is equal to the derivative of numerator over derivative of the denominator.

May 24, 2017

The value of this limit is