Question

How do you evaluate the limit of `lim (2n^2)/n` as `n->0`?

Answer 1

0

Explanation:

evaluating for n = 0 gives indeterminate form.

Simplifying the expression by cancelling.

`lim_(nto0)(2 cancel(n^2)^n)/cancel(n)^1`

`rArrlim_(nto0)2n=0`