Question

How do you evaluate the limit of `lim (2x^2-3x)/(x^3-2x^2+x+6)` as `x->3`?

Answer 1

#1/2

Explanation:

`"the limit in this case can be evaluated by direct substitution"`

`lim_(xto3)(2x^2-3x)/(x^3-2x^2+x+6)`

`=(18-9)/(27-18+3+6)=1/2`