# How do you evaluate the limit of #lim (2x^2-3x)/(x^3-2x^2+x+6)# as #x->3#?

##### 1 Answer

Apr 1, 2018

#1/2

#### Explanation:

#"the limit in this case can be evaluated by direct substitution"#

#lim_(xto3)(2x^2-3x)/(x^3-2x^2+x+6)#

#=(18-9)/(27-18+3+6)=1/2#