# How do you evaluate the limit of #lim ((x+2)^2-4)/x# as #x->0#?

##### 1 Answer

Nov 18, 2016

#### Explanation:

The function evaluated at x = 0 is

#0/0# that is indeterminate.Expand the numerator.

#(x^2+4x+4-4)/x=(x^2+4x)/x=x+4#

#lim_(xto0)((x+2)^2-4)/x=lim_(xto0)(x+4)=4#