Question

How do you evaluate the limit of `lim (x^2-25)/(x-5)` as `x->5`?

Answer 1

10

Explanation:

`lim_(x->5) (x^2-25)/(x-5) = lim_(x->5) ((x-5)(x+5))/(x-5)= lim_(x->5) (x+5) = 10`