How do you evaluate the limit of $lim (x^2-25)/(x-5)$ as $x->5$ ?

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Answer 1 · 2016-11-29T11:40:59

10

$lim_(x->5) (x^2-25)/(x-5) = lim_(x->5) ((x-5)(x+5))/(x-5)= lim_(x->5) (x+5) = 10$

How do you evaluate the limit of lim (x^2-25)/(x-5)lim (x^2-25)/(x-5) as x->5x->5?