How do you evaluate the limit #-root3(2x+2)# as x approaches #-1#?
1 Answer
Dec 1, 2016
We can directly substitute
Explanation:
We see that:
#lim_(xrarr-1)(-root3(2x+2))=-root3(2(-1)+2)#
#color(white)(lim_(xrarr-1)(-root3(2x+2)))=-root3(-2+2)#
#color(white)(lim_(xrarr-1)(-root3(2x+2)))=-root3 0#
#color(white)(lim_(xrarr-1)(-root3(2x+2)))=0#
