Question

How do you evaluate the limit `-s^2+8s-17` as s approaches `3`?

Answer 1

`lim_(s rarr c)-s^2+8s-17= -2`

Explanation:

Let `f(s)=-s^2+8s-17`, Then `f` is a polynomial and is therefore continuous over all Real Numbers, `RR`

`:. lim_(s rarr c)f(s)=f(c)`

Hence `lim_(s rarr c)-s^2+8s-17=-8+24-17= -2`