Question

How do you evaluate the limit `sec(2x)` as x approaches `0`?

Answer 1

1

Explanation:

`lim_( x to 0) sec 2x`

`=lim_( x to 0) 1/(cos 2x)`

cosine is continuous through x = 0 so we can just plug in the value

`= 1/(cos 0) = 1`